13 Mar

Solve the system of linear equations using augmented matrices.?

Posted by wktd under enart.hubeidaxue.com

  • 2x + 3y = -8
    x + y = -8

    x=?
    y=?

    If there are infinitely many solutions, let x = t.

    If there is no solution, type no in every field.





  • one solution...matrix is 2...3....-8
    .................................. 1...1...-8...multiply the 1st row by 1/2 and subtract from the 2nd to get new 2nd 0...-1/2...-4....thus y = 8 and x = -16


  • It's hard to show a matrix without an equation editor, but it would look something like this...

    [ 2 3 -8 ]
    [ 1 1 -8 ]

    The row operation that gives a zero in the lower left is: 2 R2 - R1 => new R2. This gives:

    [ 2 3 -8 ]
    [ 0 -1 -8 ]

    The row operation that gives a zero in the second column, top row is: R1 + 3 R2 => new R1. This gives:

    [ 2 0 -32]
    [ 0 -1 -8 ]

    Divide row 1 by 2, and multiply row 2 by (-1):

    [ 1 0 -16]
    [ 0 1 8 ]

    The resulting solution is:
    x = -16 and y = 8










    • #If you have any other info about this subject , Please add it free.#
    Your name:
    E-mail:
    Telphone:

    Your comments:


    If you have any other info about Solve the system of linear equations using augmented matrices.? , Please add it free.
    | |